2x^2+5x+25/4=57/4

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Solution for 2x^2+5x+25/4=57/4 equation: 


x in (-oo:+oo)

2*x^2+5*x+25/4 = 57/4 // - 57/4

2*x^2+5*x+25/4-(57/4) = 0

2*x^2+5*x+25/4-57/4 = 0

2*x^2+5*x-8 = 0

DELTA = 5^2-(-8*2*4)

DELTA = 89

DELTA > 0

x = (89^(1/2)-5)/(2*2) or x = (-89^(1/2)-5)/(2*2)

x = (89^(1/2)-5)/4 or x = (-(89^(1/2)+5))/4

x in { (-(89^(1/2)+5))/4, (89^(1/2)-5)/4 }

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